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I have an optimization like below:

$\text{ minimize } \sum_k - \log_2 x_k $

$\text{subject to: } x_k \leq q , k =1,2, \cdots, N .$

I can form the Lagrange of the problem as below:

$L(x, \lambda) = \sum_{k=1}^{N} - \log_2 x_k + \sum_{k=1}^{N} \lambda_k (x_k -q) $

But How can I find KKT conditions for this? Moreover, How can I solve the problem analytically from there? I know I can solve it through some nonlinear optimization solver software but for now I am only interested in solving the problem analytically so that I can get an exact form of x.

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The simple solution (without KKT): it is easy to see that the problem is actually decoupled, i.e. the condition $0<x_k\le q$ affects only one term $\log_2x_k$ in the objective function. It makes it possible to minimize over $x_k$ each term independently, i.e. $$ \min\sum_{k=1}^n(-\log_2 x_k)=\sum_{k=1}^n\min_{0<x_k\le q}(-\log_2x_k)= \sum_{k=1}^n(-\log_2q)=-n\log_2q. $$ The "hard" solution (by KKT): motivate first that the minimum exists. Prove that the boundary $x_k=0$ is never active at the minimum, so we can cut it off to make the set compact, the function is continuous $\Rightarrow$ can apply Weierstrass theorem. Thus, we can use KKT that looks like "$\nabla L=0$ + the complementary slackness conditions + feasibility", i.e. for all $k=1,\ldots,n$ $$ \left\{ \begin{array}{lll} -\frac{1}{x_k\ln 2}+\lambda_k&=&0,\\ \lambda_k(x_k-q)&=&0,\\ \lambda_k\ge 0,\ 0<x_k\le q. \end{array} \right. $$ The first and the third conditions give that $\lambda_k\ne 0$ for all $k$, thus, the second equation gives $x_k=q$. Substitute to the objective function to get $-n\log_2q$.

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