A man leaves office everyday at 5 p.m. His driver leaves home everyday at such a time that he can pick up his master from the office at 5 p.m. The driver drives at a constant speed. Now one day, the man left office at 4.40 p.m. and started walking towards home. On that day too the driver had left home on such a time that he could pick up his master at 5 p.m. But since the man had started walking at 4.40 p.m. they met somewhere in between from where the driver took his master home. That day, the man reached home 10 minutes earlier. One week later, a similar thing happened, the man left office at 4.50 p.m. and met the driver on his way home from where the driver took his master. How much earlier did the man reach home the second day?
Solvers, Please show your methods, because answer is 5 minutes, as expected , but how you get it is of interest.