a three-character password consists of 2 different digits between 0 and 9 inclusive. and 1 letter of the English alphabet. the letter must appear as first or second character, how many different passwords are possible?
I assumed that they are not case sensitive. So there is 26 possible letters for the first alphabet, then there is 10 digits for the second place and 9 digits for the third place. Redo the steps again and assume the letter is in second place. 10*26*9. I used permutation 26P1 * 10P2 so (26*10*9)^2=2340^2=5475600
But this answer is incorrect. Can somebody point out where i went wrong? :)
Thanks in advance :)