"In drawing two cards from a deck (without returning the first card) what is the probability of two aces when you get at least one ace?"
Are my calculations correct?
- $4*51$ possible events with an ace on the first draw
- $52*4$ with an ace on the second draw
- $4*3$ with an ace on both draws
Thus we have $4(51+52+3) = 4(106)$ events with at least one ace.
$(4*3)/(4*106) = 3/106$ is the probability of two aces when you get at least one ace.