# Strong law of large numbers [duplicate]

Suppose $X_i\in\mathcal{L}^2$ with expectation $0$ such that $\sum_{i=1}^\infty \mathbb{E}[X_i^2]/i^2<\infty$ and suppose they are pairwise non correlated. Does then the SLLN still hold?

## marked as duplicate by davidlowryduda♦Oct 7 '15 at 20:33

• I don't have any answer ready yet but if $\sum \frac{X_i}{i}$ converges a.s. then SLLN follows from Kronecker's Lemma as $n \uparrow \infty$. – Saty Aug 6 '15 at 18:47
If you want to impose just uncorrelatedness between the variables in the sequence rather than independence, then you need to impose a stronger condition than $\sum_{i=1}^{\infty} Var[X_i]/i^2 < \infty$. To be more precise, a sufficient condition in this case that will guarantee SLLN is the following: $$\sum_{i=1}^{\infty} Var[X_i] \left(\frac{log \, i}{i}\right)^2 < \infty.$$