If we have $x+(x \cdot y)$, is it possible to simplify this, on having only one single x?

How can we make those two X together?

  • $\begingroup$ Rewrite the first $x$ to $x\cdot 1$; then use the distributive law. $\endgroup$ – Henning Makholm Jul 16 '15 at 13:46
  • $\begingroup$ Have you notice the L ? Can you please elaborate? Thank you. $\endgroup$ – mem Jul 16 '15 at 13:53
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    $\begingroup$ $x+(x\cdot l)=x\cdot (1+l)$. Also you never want your two x's together. $\endgroup$ – Thibaut Dumont Jul 16 '15 at 13:54
  • $\begingroup$ I will change the L for y. $\endgroup$ – mem Jul 16 '15 at 13:54

We can "combine like terms". We have: $$ x + xy = (1\cdot x) + (y \cdot x) = (1 + y)\cdot x = x\,(y+1) $$ In general, this is referred to as "factoring". In this case, we "factored out" an $x$.


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