0
$\begingroup$

If we have $x+(x \cdot y)$, is it possible to simplify this, on having only one single x?

How can we make those two X together?

$\endgroup$
  • $\begingroup$ Rewrite the first $x$ to $x\cdot 1$; then use the distributive law. $\endgroup$ – Henning Makholm Jul 16 '15 at 13:46
  • $\begingroup$ Have you notice the L ? Can you please elaborate? Thank you. $\endgroup$ – mem Jul 16 '15 at 13:53
  • 1
    $\begingroup$ $x+(x\cdot l)=x\cdot (1+l)$. Also you never want your two x's together. $\endgroup$ – Thibaut Dumont Jul 16 '15 at 13:54
  • $\begingroup$ I will change the L for y. $\endgroup$ – mem Jul 16 '15 at 13:54
1
$\begingroup$

We can "combine like terms". We have: $$ x + xy = (1\cdot x) + (y \cdot x) = (1 + y)\cdot x = x\,(y+1) $$ In general, this is referred to as "factoring". In this case, we "factored out" an $x$.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.