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So I have a solid with a semicircular base of radius 19. The cross sections are perpendicular to the base and parallel to the diameter and these cross sections are squares.

The semi circle is placed on the xy plane so that the diameter is on the x axis and it is centered on the y axis.

I need help setting up the integral that will give the volume of the solid. I don't know how to go about it. I've read a bit and the only thing I can figure out is that it is bounded from 0 to 19 as the integral boundary.

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the semi-circle is centred on the origin, so its equation is $ x^2+y^2=19^2: y \ge 0$

so for any given $y$ the integrand must be the area of the square whose sides are $2 \sqrt{19^2-y^2}$

$$V=4\int_0^{19} (19^2-y^2) dy$$

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  • $\begingroup$ Thanks! What are x and y in the circle equation. I know they equal to the radius but what are they initially? $\endgroup$ – code Jun 25 '15 at 19:23
  • $\begingroup$ they are the co-ordinates of the $xy$ plane you mention in your question $\endgroup$ – WW1 Jun 25 '15 at 19:31

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