# Every metric space with a countable base is separable

I know that every separable metric space has a countable base.

I was wondering if we can get a countable dense subset from every metric space that has a countable base.

Thank you very much!!

In general in any topological space let $A=\{a_i : a_i \in O_i\}$ you can prove that $A$ is a dense countable subset, such that $B=\{O_i : i \in\mathbb N\}$ is the Base of topological space