You roll a dice 1000 times. Calculate the probability you roll a six between 150 and 200 times. I understand how you calculate this with the binomial distribution: $$ = Binomialcdf(1000, 1/6, 200) - Binomialcdf(1000, 1/6, 149) = 0.9975-0.0710=0.9265 $$
How do you do this with the normal distribution? The answer should be 92.53%. Problem is when I use Normalcdf(200) - Normalcdf(150) I get 0.9190 What am I doing wrong?
My second question: If you roll exactly 200 times a six, what is the probability there will be less than 150 times a five? Again I understand how I could calculate it with the binomial distribution, but not with the normal distribution... Answer should be 20.04%