Set Notation Probability 
I don't understand how I would do this question when it does not have any values to work with.
Any ideas? Thank you.
 A: In a standard deck of cards there are $52$ cards, $4$ different suits (hearts, diamonds, clubs, and spades), and $13$ different values for the cards ($A$, $2$, $3$, ..., $9$, $J$, $Q$, $K$).
Additionally, each suit has a colour. Hearts and diamonds are red, and clubs and spades are black.

Now just an explanation of notation:
Suppose we have two events, $A$ and $B$.
When we say $P(A \cap B)$, we are saying the "probability that both events $A$ and $B$ occur".
When we say $P(A \cup B)$, we are saying the "probability that events $A$ or $B$ occur".
For example:
In a), you are asked for $P(Q \cap D)$. This is like asking for the probability that a card you choose is both a queen and a diamond. As you previously stated in a comment, this occurs only once because there is only one queen of diamonds in the deck of cards. So you have $1$ card out of $52$ total in a deck that you can choose. Simply, that is a probability of $1/52$.
Likewise, in b) you are asked for $P(Q \cup D)$, which is like asking for the probability that a card you choose is a queen or a diamond.
I will leave the rest up to you, but if you need help, don't hesitate to ask!
A: Let's do an example, part (a). Part (a) asks for the probability that a random card is queen diamond. Since there is only one such card and 52 cards in total, the probability is 1/52.
Part (b) asks for the probability that a random card is a queen or a diamond; part (c) asks for the probability that a random card is not a queen or is a diamond; and part (d) asks for the probability that a random card is a queen other than queen diamond. In all cases, the answer is N/52, where N is the number of cards satisfying the requirements.
