$ dy = \frac{1}{1+x^{2}} dx $
How would I integrate this ? Can I use a u substitution?
let $ u = 1+x^{2} dx $
$ du = 2x dx $
am not sure how to go from here?
Any help appreciated thanks
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Sign up to join this community$ dy = \frac{1}{1+x^{2}} dx $
How would I integrate this ? Can I use a u substitution?
let $ u = 1+x^{2} dx $
$ du = 2x dx $
am not sure how to go from here?
Any help appreciated thanks
The integral of $\frac{1}{1+x^2}$ is equal to $\tan^{-1}(x)$, so you can evaluate your expression to give $y = \tan^{-1}(x) + c$
The solution is $y=\arctan x+c$ using the standard integral