I am in a prob and stats course... haven't taken one in awhile and would like some help on these two problems. I think I am probably making these a little two simple.
Four married couples have bought 8 seats in a row for a concert. In how many ways can they be seated if:
a. if each couple sit together? 4!2!2!2!2!= 384
b. if all men sit together?
I am thinking of this M1M2M3M4W1(Any women)(Any Women)(Any Women)(Any Women) so 4*3*2*1*4*3*2*1= 576