Can the expression be made true after replacing the blanks in this sum with 2 numbers from 0-9 and 2 symbols? The expression is 
$$
2\_\,\_\,\_\,\_5=2015 
$$
you have to replace 2 of the blanks with digits (0-9), and the other 2 with one of the operations $+- \times \div$.  Is it possible to make the expression true? 
 A: Since you need two digits and two operators, the resulting expression would involve one $2$-digit number and two single digit numbers.
Now note that the largest such expression that fits the prompt is
$$
2*9*95 = 1710 < 2015
$$
thus the problem doesn't admit any solution.

In my previous answer, I showed that the only two solutions with one operator and three digits are:
$$
2010 + 5 = 2015
\qquad \text{and} \qquad
2020 - 5 = 2015
$$
A: There are no solutions that solve the prompt as given.  I made the below Python script to run through the possibilities without leading zeros.  You can then go through the possibilities with leading zeros separately and note that clearly, none of them are solutions.
operations = ['+','-','*','/']
expchars = [0,0,0,0]
solution = "no solutions"
done = False

for c in operations:
    for d in operations:
        for m in range(2):
            for n in range(m+2,4):
                numindex = range(4)
                numindex.remove(m)
                numindex.remove(n)
                for s in range(10):
                    for t in range(10):
                        expchars[m] = c
                        expchars[n] = d
                        expchars[numindex[0]] = str(s)
                        expchars[numindex[1]] = str(t)
                        while not done:
                            done = True
                            exp = "2" + ''.join(expchars) + "5"
                            try:
                                if eval(exp) == 2015:
                                    solution = exp
                            except ZeroDivisionError:
                                #print("divided by zero: " + exp)
                                pass
                            except SyntaxError:
                                done = False
                                #print("leading zero: " + exp)
                                if s == 0:
                                    expchars[numindex[0]] = ' '
                                if t == 0:
                                    expchars[numindex[1]] = ' '


print(solution)

