Taylor theorem equation I have one question about Taylor theorem.
Originally, Taylor theorem is represented as
$$f(x) = f(a) + f'(a)(x-a) + \ldots$$
But my book says
Suppose that $$f : \mathbb{R}^n \to \mathbb{R}$$ is continuously differentiable and that $p\in\mathbb{R}^n$
Then we have that
$$f(x + p) = f(x) + ∇f(x+tp)^Tp$$
But I don't understand how to derive this equation from Taylor theorem.
 A: This equality follows from the mean value theorem applied to the function $ g (s) = f (x + sp) , 0 \leq s \leq 1$.
By the mean value theorem, there exists $ t \in (0,1)$ such that $ g (1) -g (0) = g'(t) = \nabla f (x + tp)^T p$.
A: The formula you have is incorrect (what is $t$ anyway?); it should be $\nabla f(x)^T$ at which point it is simply Taylor's theorem for functions of several variables.
A derivation of the multivariate Taylor's theorem should be covered in any introductory textbook on multivariable calculus; I'm very surprised that yours does not. There are plenty of course notes available online that also explain it, for instance here.
EDIT: Looking at Nocedal and Wright it seems that what you are actually after is the multivariate mean value theorem: for $f$ differentiable in a sufficiently large neighborhood of $x$, there exists a $t \in [0,1]$ with
$$f(x+p) = f(x) + \nabla f(x+tp)^Tp.$$
You can see this directly from the single variable mean value theorem, see e.g. the Wikipedia entry.
