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What would this simplify to?

I got $\frac{4}{-3x+4}$. I don't think that is right. Would it just be -3x??

I get stuck here. $\frac{x^2-x-12}{x^2-3x-4}\times\frac{x^2-1}{x^2+2x-3}$

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    $\begingroup$ In this case, factoring is useful. We get $\frac{(x-4)(x+3)}{(x-4)(x+1)}\times \frac{(x-1)(x+1)}{(x+3)(x-1)}$. Now you can finish. Lots of cancellation! $\endgroup$ Commented Jun 2, 2015 at 22:29

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factoring gives $$\frac{(x-4)(x+3)}{(x-4)(x+1)}\times\frac{(x+1)(x-1)}{(x+3)(x-1)}$$ now we can cancel out terms everything cancels to $1$. So in the end, no nasty multiplication was required.

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    $\begingroup$ Are you sure you canceled correctly? $\endgroup$ Commented Jun 3, 2015 at 2:15

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