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I need help with this problem,
$$\int_0^4|x^2 - 2|x||dx$$
what should I do with $2|x|$ ?
May 28, 2015 at 19:18
Conveniently, your integration limits are $(0,4)$ so the inside absolute value can be ignored. You are left with the following:
$$\int_0^4 |x^2 - 2x| \ dx = \int_0^4x\cdot|x-2|\ dx$$
$$= \int_0^2 x\cdot(2-x)\ dx + \int_2^4x\cdot(x-2) \ dx$$
I leave the rest to you.
May 28, 2015 at 19:50
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