Infinite many curves passing through finite points? Let $R$ be a Noetherian domain of dimension two. 

Let $\mathfrak{m}_1,\mathfrak{m}_2$ be two distinct maximal ideals of height two. Are there always infinitely many prime ideals contained in $\mathfrak{m}_1\cap\mathfrak{m}_2$? 

I have done the following case:
Let $k$ be an algebraically closed field. Let $R=k[x,y]$. Let $\mathfrak{m}_1, \mathfrak{m}_2,\ldots,\mathfrak{m}_r$ be $r$ distinct maximal ideals. Then there are infinitely many prime ideals $\mathfrak{p}\subset \bigcap_{i=1}^r \mathfrak{m}_i$.
Proof: By Nullstellensatz, write $\mathfrak{m}_i=(x-a_i,y-b_i)$. If all $a_i$ are distinct. Then we may find a polynomial $F=y-f(x)$ which is irreducible (i.e. the interpolation polynomial). And we may add more points to get more different irreducible polynomials. 
Since $\mathfrak{m}_i$ are distinct pairwise. We can always find a linear transformation $A\in GL_2$ so that we come back to above. Here it will use the field $k$ is infinite. 
Corollary This is true for $\mathbb{A}^2_k$ for any field $k$. 
It seems that it is difficult to go more far. 

Let $A$ be a finitely generated $k$-algebra which is a domain of dimension two. Let $\mathfrak{m}_1\neq\mathfrak{m}_2$ be two maximal ideals. I am even unable to  find a prime ideal $0\neq\mathfrak{p}\subset \mathfrak{m}_1\cap\mathfrak{m}_2$.

Thanks.
 A: It is well known that if $A$ is a PID then the non-maximal prime ideals of $A[x]$ are principal.
Let $A$ be a DVR with uniformizing parameter $t$ and let $R = A[x]$ be the ring of polynomials with coefficients in $A$. For every non-negative integer $n$, the ideal $\mathfrak{m}_n = (t^n x -1)$ is maximal because $R / \mathfrak{m}_n$ is the field of fractions of $A$. Pick the product (i.e the intersection) $I$ of a finite number of $\mathfrak{m}_n$'s. $I$ is a principal ideal and $\{ 0 \}$ is the only prime ideal contained in $I$.
A: For a variety of dimension $n$ over an algebraically closed field, and finitely many closed points, you can always find infinitely many irreducible positive dimensional subvarieties passing through all of them.  In your situation, the closed points correspond to maximal ideals, and you can actually find infinite primes in their intersection (i.e. irreducible subvarieties passing through those points) of any fixed height $c$ (i.e. codimension $c$), for $c=1, \ldots , n-1$.  This is done by reducing to the case where your variety is projective (via Chow's lemma), blowing up the points in question, and using Bertini's theorem.  This does it for the case where your ring is an affine domain, i.e. a finitely generated algebra over an algebraically closed field which is a domain.
