I'm going through a paper on turbulence and in it the author uses the following $$ \nabla\times(\vec{b}\cdot\nabla)\vec{b}=(\vec{b}\cdot\nabla)(\nabla\times\vec{b})-\left((\nabla\times\vec{b})\cdot\nabla\right)\vec{b} $$ however I have tried to verify this with both vector analysis identities and using suffix notation and I can't seem to do so. I wondered if anyone could either show why it holds or correct it. Thanks in advance.

  • $\begingroup$ Do you know how to compute the curl of a vector field and the divergence of a vector field? I'm assuming $\vec{b}$ is your given vector field. $\endgroup$ – MathNewbie May 22 '15 at 11:09
  • $\begingroup$ Sorry I meant I used both methods, as in manipulating standard vector identities and using suffix notation. The specific identity I tried to apply was $$ \nabla\times(\psi\vec{A})=\psi\nabla\times\vec{A}+\nabla\psi\times\vec{A} $$ since $ \vec{b}\cdot\nabla$ is a scalar this seemed the most appropriate. However this didn't yield the correct result for me. $\endgroup$ – Nick Bell May 22 '15 at 11:12
  • $\begingroup$ Yes I do know how to compute the curl and the divergence and yes b is my vector. But it is an algebraic quantity and so I do not have numeric values for the vector so can't do a direct calculation. $\endgroup$ – Nick Bell May 22 '15 at 11:14
  • $\begingroup$ Well $\vec{b}$ should be a vector field. Not sure what you mean by an algebraic quantity, but write out $\vec{b}$ in terms of its three components. $\endgroup$ – MathNewbie May 22 '15 at 11:17
  • $\begingroup$ I realise that you could do that to verify the equivalence. But I was more hoping for an explanation of how you get from the left hand side to the right hand side using standard vector manipulation. eg identities, product rules etc. $\endgroup$ – Nick Bell May 22 '15 at 11:27

EDIT: It turns out the identity is incorrect. Consider the vector field $\vec{b}=\begin{pmatrix}xy\\0\\xy\end{pmatrix}$ (it doesn't work)

  • $\begingroup$ Thank you! Although it is in fact that last bit that I was having trouble with! $\endgroup$ – Nick Bell May 22 '15 at 11:46
  • $\begingroup$ Perhaps I was being a bit hopeful in saying this hopefully isn't too hard... I can't seem to verify it! I'll leave this up for the time being and come back to it when I work it out. $\endgroup$ – preferred_anon May 22 '15 at 13:26
  • $\begingroup$ EDIT: It turns out the identity is false. See the above for a counterexample (I leave verifying it as an exercise to the reader!) $\endgroup$ – preferred_anon May 22 '15 at 17:22
  • $\begingroup$ Ahhh yes you are right! Now to see how badly this error affects the paper!! $\endgroup$ – Nick Bell May 22 '15 at 18:21
  • $\begingroup$ I'm curious as to what the actual identity is. Perhaps there's a typo or something of that sort. $\endgroup$ – MathNewbie May 22 '15 at 22:50

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