How to get all the decimals on a division with decimal point and without remainder? I divided 4.18 by 5 by hand, like this:
As you see I removed the decimal point since I was dividing by a whole number, then I put the decimal point back and got 0.83 as result.
It's correct, the point is that often on this kind of division I get a remainder (in this case is 3), and I suppose this isn't right. 
By the way, a calculator returns 0.836 for 4.18/5, which means I'm missing at least one decimal place.
My question is, how do I solve division with decimal points so that I get all the decimal places. Is it ok to have a remainder?
Thanks
 A: \begin{array}{cccccccccc}
& & 0 & . & 8 & 3 & 6 \\  \\
5 & ) & 4 & . & 1 & 8 & 0 \\
  &   & 0 \\  \\
  &   & 4 &   & 1 \\
  &   & 4 &   & 0 \\  \\
  &   &   &   & 1 & 8 \\
  &   &   &   & 1 & 5 \\  \\
  &   &   &   &   & 3 & 0 \\
  &   &   &   &   & 3 & 0 \\  \\
  &   &   &   &   &   & 0
\end{array}
The algorithm stops there because $0$ appeared as the remainder.
Where you have $4.18$ you can write $4.1800000000\ldots$ with as many $0$s as necessary.
A: By removing the decimal place, you are essentially computing $$\frac{418}{5},$$ which is exactly $100$ times your desired result.
In your computation, you obtain $$\frac{418}{5} = 83\ R3 = 83 + \frac{3}{5}.$$
This is equal to $83.6$; since this result is 100 times your desired result, divide by 100 to get
$$\frac{4.18}{5} = \frac{1}{100} \times \frac{418}{5} = \frac{1}{100}\times 83.6 = 0.836.$$
A: The trick to these is to change the number so that it is easier to use, but has the same value. notice that $4.18 = 4.180=4.1800=\cdots$ so you can always add another $0$ onto the end of a decimal number and it will retain its value. In this case if you add a $0$ you will bring it down to the $3$ and need to find how many $5$'s go into $30$ and the answer is $6$. For a general problem, you will need to keep doing this until either you do not get a remainder, such as in this case, or you see a pattern in the decimals, in a problem such as $1÷3 = .333333333\ldots$ In the second case we can write the answer as simply $. \bar{3}$
