3
$\begingroup$

Is it true that the first Chern class of a rank $k$ complex line bundle is equal to the first Chern class of its determinant line bundle?

$\endgroup$
2
  • $\begingroup$ I need a "yes or no" answer only! $\endgroup$ May 14, 2015 at 18:18
  • $\begingroup$ See also this. $\endgroup$ May 14, 2015 at 22:12

1 Answer 1

7
$\begingroup$

Yes. You may use the splitting principle and assume that the vector bundle is a direct sum of $k$ line bundles, and note that the first Chern class of direct sum of line bundles is the sum of first Chern classes of the line bundles, which in turn is the Chern class of the tensor product of those bundles, which is isomorphic the top wedge power of the original vector bundle.

$\endgroup$
1
  • $\begingroup$ Ok, tank you very much! Good argument. $\endgroup$ May 14, 2015 at 18:52

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .