# Integrating a product of to error functions and an exponential

I have the following integral that I need to solve.

$\int_{-\infty}^\infty \exp(-\frac{x^2}{2})*\text{erf}(x-\delta)*\text{erf}(x-\gamma)dx$

I was hoping I could use this: Integral of product of exponential function and two complementary error functions (erfc)

• Actually the case with $\delta=\gamma=0$ can be solved using 8.258 2) in lepp.cornell.edu/~ib38/tmp/reading/… and 4.3-2 here: nvlpubs.nist.gov/nistpubs/jres/73B/jresv73Bn1p1_A1b.pdf. And since $\int_{-\infty}^\infty \text{erf}(x)^2\text{exp}(-x^2/2)=\frac{1}{2}\int_{0}^\infty \text{erf}(x)^2\text{exp}(-x^2/2)$.... the result is easy to get. – Klein Gordon May 14 '15 at 12:08
• Sorry, the $\frac{1}{2}$ on the rhs of the last equation should be a $2$. – Klein Gordon May 14 '15 at 13:06
• You're right. Maple can evaluate it, but Mathematica can't $($for some mysterious reason$)$. – Lucian May 14 '15 at 17:26