The decimal expansion of the quotient of two integers It is an exercise in a book on discrete mathematics.How to prove that in the decimal expansion of the quotient of two integers, eventually some block of digits repeats.
For example:
$\frac { 1 }{ 6 } =0.166\dot { 6 } \ldots$ and $\frac { 217 }{ 660 } =0.328787\dot { 8 } \dot { 7 } \ldots$
How to think of this?I just can't find the point to use the Pigeonhole Principle.
Thanks for your help!
 A: Let's proceed to the actual division :
$
\begin{array} {r|l}
\boxed{217}\hphantom{000\;} & 660\\
\hline
2170\hphantom{000}  & 0.3287\\
-1980\hphantom{000}   & \\
\boxed{190}\hphantom{00\;}   & \\
1900\hphantom{00}   & \\
-1320\hphantom{00} & \\
\boxed{580}\hphantom{0\;}  & \\
5800\hphantom{0}  & \\
-5280\hphantom{0}  & \\
\boxed{520}\hphantom{\;}  & \\
5200  & \\
-4620  & \\
\boxed{580}  & \\
\end{array}
$
The important point is that the remainders must be smaller than the quotient $660$ so that, after a finite number of operations, you must get $0$ or a remainder you got before.
What will the next digit of the quotient be? And the next remainder?
Hoping it clarified,
A: Assume the decimal is infinite (otherwise the 0 repeats). Imagine evaluating the quotient by long division. After each step after the numerator has become all 0's, you have to carry over something less than the denominator. Eventually you'll have to carry something you carried before, because you carry something on every step.
