From Morris, A. O., Linear Algebra, an introduction (2nd edition, Van Nostrand, 1989) he gives the following as not being an inner product.

$(u,v)=x_1y_1-x_2y_1-x_1y_2+2x_2y_2$, where $u=(x_1,x_2),v=(y_1,y_2)$

My working below shows otherwise. Where do I go wrong?

Let $w=(z_1,z_2)$







Similarly $(\alpha u,v)=\alpha(u,v)$

$(u,v)=(v,u)$ can easily be verified, and



$(x_1-x_2)^2+x_2^2 >0$ if $u \neq 0$.

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    $\begingroup$ You should remove the leading spaces from your display equations in order for MathJax to render them properly. Also, you might find the $\mathtt{align}$ environment helpful for aligning your equations in a particularly nice way. $\endgroup$ – Travis Willse May 5 '15 at 15:09
  • $\begingroup$ Sorry I did not write the Latex code correctly for the subscripts and superscripts $\endgroup$ – Zilore Mumba May 5 '15 at 15:39

That product can be written as $$ (u, v) = u^{t} A v $$ where $$ A = \begin{pmatrix} 1 & -1 \\ -1 & 2 \end{pmatrix}. $$ Since $A$ is symmetric, this is a perfectly good inner product as you've already shown. It's even positive-definite since $$ (u,u) = x_1^2 - 2x_1 x_2 + 2x_2^2 = (x_1-x_2)^2 + x_2^2 $$ is semipositive, and zero if and only if $x_1 = x_2 = 0$. Morris must have meant to write something else, but good for you to find the error!

  • $\begingroup$ Thanks so much @Gunnar Þór Magnússon $\endgroup$ – Zilore Mumba May 5 '15 at 19:38

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