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I figured out that the top is (2x-1) and that the difference between the denominator ends up being (2x-1), just not sure how to figure out what the series is.

alternating series

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  • $\begingroup$ Have you tried finding a quadratic expression for the denominator? $\endgroup$ – JimmyK4542 May 4 '15 at 4:00
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By using the EOIS site, I found the general term for the denominator is $a_n = (n-1)^2+1$, I think you should be able to continue..

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