# Triangles, sine and cosine problem

Hi everyone I tried solving this countless times but I always get the wrong answer! what I did first is 600/tan(46) - 600/tan(40) and that sounded reasonable to find the answer! but I keep getting it wrong :( there was a similar question but I got it right.

Thank you.

• the two distances should be added; not subtracted. – abel May 4 '15 at 0:32
• That actually worked, thanks! – AliAlM May 4 '15 at 0:37
• you are welcome. what do you mean actually? were you expecting not to work? – abel May 4 '15 at 0:39

$tan40^\circ=\frac{600}{x}$
$tan46^\circ=\frac{600}{y}$
So,Distance = $(x+y)=\frac{600}{tan40^\circ}+\frac{600}{tan46^\circ}$
$=6oo(\frac{1}{tan40^\circ}+\frac{1}{tan46^\circ})$