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I have:

$(1 \frac{9}{16}) ^\frac{3}{2}$

and the answer given is:

$\frac{125}{64}$

I'm not sure the order in which everything was done to get the answer. Also, does anyone know of a site like WolframAlpha but which shows the step by step progress of a maths problem?

Thank you!

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2 Answers 2

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$$(1 \frac{9}{16}) ^\frac{3}{2}=(\frac{25}{16})^\frac{3}{2}=((\frac{5}{4})^2)^\frac{3}{2}=(\frac{5}{4})^3=...$$

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  • $\begingroup$ That's great, thank you! $\endgroup$
    – penpen
    Mar 29, 2012 at 12:39
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    $\begingroup$ Welcome to math.SE! It is my pleasure. $\endgroup$
    – Salech Alhasov
    Mar 29, 2012 at 12:42
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$$\left(1 \frac{9}{16} \right)^{3/2} = \left(\frac{25}{16}\right)^{3/2} = \left(\frac{25}{16}\right)^{2/2} \cdot \left(\frac{25}{16} \right)^{1/2} = \frac{25}{16} \cdot \frac{5}{4} = \frac{125}{64}.$$

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