A triangle with side 8 inches and corresponding angle 13 degrees, side x inches and corresponding angle 120 degrees.
To answer this I set up a proportion:
$\sin \left(13\right)/8=\sin \left(120\right)/x$
$x\sin \left(13\right)=8\sin \left(120\right)$
$x=8\sin \left(120\right)/\sin \left(13\right)$
The information from the triangle is right, but the answer is not listed, as it should be. Have I done something wrong mathematically or is the book wrong.