An R-matrix in a quasitriangular Hopf algebra I am new to the theory of Hopf algebra. So I am sorry if the following question has really trivial answer.
Suppose that we have a quasi triangular Hopf algebra with the universal R-matrix $R$. It satisfies the following equation by definition:
$$(\Delta \otimes \mathrm{id})(R)=R_{13}R_{23}$$
where
$\Delta$ is the comultiplication and $ R_{13}=\phi_{13}(R)$ with $\phi_{13}(a\otimes b)=a\otimes 1 \otimes b$ and $ R_{23}=\phi_{23}(R)$ with $\phi_{23}(a\otimes b)=1\otimes a \otimes b$.
Let us write $R=\sum e_i\otimes f_i$. Let $R'=\sum f_i \otimes e_i$.
My question is whether we can replace $R$ with $R'$ in the above equation. Namely:
Is
$$(\Delta \otimes \mathrm{id})(R')=R'_{13}R'_{23}$$
hold true?
 A: In general the identity : $$(\Delta \otimes id)R'=R'_{13}R'_{23}\qquad (E)$$
does not hold (See Counterexample below). But it is true that $R'$ satisfy the conditions of "quasi-triangularity" with respect to $\Delta^{op}$ and therefore, we have :
$$(\Delta^{op} \otimes id)R'=R'_{13}R'_{23}\qquad (E)$$
$\textbf{Counterexample:}$
Le $H$ be the Sweedler's algebra like in http://en.wikipedia.org/wiki/Sweedler%27s_Hopf_algebra.
Sweedler's hopf algebra is quasi-triangular with respect to: 
$$R=\frac 1 2 (1\otimes 1 +1\otimes g + g\otimes 1-g\otimes g) +\frac \lambda 2 (x\otimes x+x\otimes gx+gx\otimes gx -gx\otimes x), $$
this is given in Kassel's quantum groups.
Let us take $\lambda=1$ ($\lambda\neq 0$ works). 
We have $R'=R+R''$ with $R''=gx\otimes x-x\otimes gx$. 
Assuming that $R'$ satisfies $(E)$ we get : 
$$ (\Delta \otimes id)R''= R_{13} R''_{23}+R''_{13}R'_{23}\qquad (*).$$ 
Denote $V_a=a\otimes H\otimes H$ and $W=V_x\oplus V_g \oplus V_{xg}$. 
Direct computation shows that : 
$$(\Delta \otimes id)R''\in -(1\otimes x\otimes gx)+W.$$ 
On the other hand, since $R''_{13} \in W$ and $ R'_{23} \in V_1 $, using that $W\cdot V_1 \subset W$ gives that $R''_{13}R'_{23} \in W$. So if (*) holds we should have :
$$ R_{13} R''_{23} \in  -(1\otimes x\otimes gx)+W \qquad(**).$$ 
Let us compute. We see that $R_{13} \in 1\otimes 1\otimes \frac{1+g}{2} +W $ and $R''_{23}\in V_1$. Therefore : 
$$ R_{13} R''_{23}\in (1\otimes 1\otimes \frac{1+g}{2})R''_{23} +W.$$ 
Finaly, we check that : 
$$ (1\otimes 1\otimes \frac{1+g}{2})R''_{23} \notin  -(1\otimes x\otimes gx)+W .$$
Wich leads to a contradiction.
