I'm doing this exercise:
Find all the subgroups of $G=\displaystyle\normalsize{\mathbb{Z}/2\mathbb{Z}\times \mathbb{Z}/4\mathbb{Z}}\LARGE_{/}\large_{\langle(1,0)\rangle}$
This is my try:
First, we see that $$\Large\mid\displaystyle\normalsize{\mathbb{Z}/2\mathbb{Z}\times \mathbb{Z}/4\mathbb{Z}}\LARGE_{/}\large_{\langle(1,0)\rangle}\Large\mid\normalsize=\displaystyle\frac{2\cdot 4}{2}=4,$$ which, by Lagrange's Theorem, means that the subgroups of the group $G$ must have order $1$, $2$, or $4$.
We classify the objects on $G$ and we end up with this table: \begin{array}{|c|c|c|}\hline Order & Elements \\\hline 1 & \{(0,0)\} \\\hline 2 & (0,2), (1,2), (1,0) \\\hline 4 & (1,1), (1,3), (0,1), (0,3) \\\hline 8 & / \\\hline \end{array}
Now we start classifying subgroups:
Subgroups generated by $1$ element:
$\large·$ $\langle (0,0)\rangle=\{(0,0)\}$
$\large·$ $\langle (0,2)\rangle=\{(0,0),(0,2)\}$
$\large·$ $\langle (1,2)\rangle=\{(0,0),(1,2)\}$
$\large·$ $\langle (1,0)\rangle=\{(0,0),(1,0)\}$
$\large·$ $\langle (0,1)\rangle=\langle (0,3)\rangle=\{(0,0),(0,1),(0,2),(0,3)\}$
$\large·$ $\langle (1,1)\rangle=\langle (1,3)\rangle=\{(0,0),(1,1),(1,3),(0,2)\}$
Now I have to find the subgroups generated by $2$ elements, but I don't know if I'm doing correctly the exercise, if there's another way to do this kind of exercises or if I made a mistake at any point, because we don't have any example like this on our class notes.
Anybody could say me how to proceed in order to find the subgroups generated by $2$ elements? Thank you.