Is there a closed-form summation result for Fourier series:
$$\sum_{n=1}^{\infty}\frac{\sin(n)}{n^4}?\tag{1}$$
I tried using available result of the following (odd) function :
$$\frac{\pi-x}{2}=\sum_{n\geq 1}\frac{\sin(nx)}{n}.\tag{2}$$
However I couldn't get the series to agree because when I integrate the formula to evaluate coefficients, the powers of $n$ become odd..