Question about an exercise from Feller The following is an exercise from the classical textbook of Feller on probability theory.

Four girls take turns at washing dishes. Out of the total of four breakages, three were caused by the youngest girl. Was she justified in attributing the frequency of her breakages to chance?

This is a variant of the balls and bins problem and we are asked to compute the probability of $3$, out of $4$ indistinguishable balls, ending up in a specific bin, which I think is given by 
$$ \frac{4 \times 3} {4^4}=\frac{12}{256}$$
Feller seems to disagree, however. The textbook solution to this problem is $\frac{13}{256}$, without any further explanation though. It's not at all obvious to me where the $13$ comes from, I have to say. Could this be a typo? Or perhaps I am missing something in the problem?
Thank you.
 A: There is a tradition in frequentist statistics to measure the significance of a result by how small the probability is of observing by chance that result or an equally extreme or more extreme result.  
The youngest sister breaking all four items is certainly more extreme than her breaking three, and this is probably why its probability was included in the calculation of what is effectively a one-tailed test, adding up all the probability in the tail to give $\frac{13}{256}$.
What is less clear is whether the oldest sister breaking three items is as extreme; if so, and similarly with the other sisters, then the answer would be $\frac{52}{256}$, which is starting not to look so significant.  The youngest sister should demand a four-tailed test.   
A: It's probably a typo, unless he meant that "at least three were caused by the youngest", which would give you a 1/4^4 chance extra, giving you the 13 in the numerator. So perhaps he meant that the older girls saw the young girl break 3 dishes, and everyone disagrees on who broke the 4'th.
