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I'm not sure how to calculate this:

If $g(t)=t^3$ and $f(x,y,z)=x^2+y^2z$, what is $g[f(1,1,3)]$?

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    $\begingroup$ Can you calculate $f(1,1,3)$? $\endgroup$
    – JessicaK
    Commented Mar 31, 2015 at 0:21
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    $\begingroup$ $g[f(1,1,3)]=(f(1,1,3))^3$. $\endgroup$
    – user26486
    Commented Mar 31, 2015 at 0:22
  • $\begingroup$ wow, i feel dumb. thank you $\endgroup$
    – user179523
    Commented Mar 31, 2015 at 0:24

1 Answer 1

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$f(1,1,3) = 1^2 + 1^2*3 = 4$

$g(4) = 4^3 = 64$

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