1
$\begingroup$

The set is $$\{ x \in Q:x^2 =64/25 \} $$

I thought the answer was $\{ \frac{8}{5}, -\frac{8}{5} \}$ but I am told there are in fact 4 distinct elements:

$$\{ \frac{8}{5}, \frac{8}{-5}, \frac{-8}{5}, \frac{-8}{-5}, \}$$

So are there 2 elements in the set or 4?

$\endgroup$
  • 1
    $\begingroup$ Unless the question is worded strangely, your answer was right. The second and fourth elements there are usually omitted in every form of arithmetic I've ever used (since they're equivalent). $\endgroup$ – co9olguy Mar 30 '15 at 17:49
  • 1
    $\begingroup$ What is $Q$? Just the set of rational numbers? It it's some kind of set $\{(a, b): a, b \in \Bbb Z\}$ and each pair gets identified with a sort of formal fraction $\frac{a}{b}$ but without the equivalence relation we put on $\Bbb Q$, then I could see $4$ elements. $\endgroup$ – pjs36 Mar 30 '15 at 17:52
  • $\begingroup$ Q is $\mathbb{Q}$ $\endgroup$ – Greg Mar 30 '15 at 18:10

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.