Use the discriminant to determine the number of points of intersection of the line $y=3x+5$ and the quadratic functions $f(x)=3x^2-2x-4$. Solve to find the points of intersection.
Using the discriminant, I got $133$, which is a positive value; therefore there should be $2$ $x$-intercepts ($2$ intersections between parabola and line). Then calculating the zeros (in this case, points of intersection) using the quadratic formula, I got $x = 6.08876$ or $x = 2.24457$.
Apparently the right answer is $x = -1.089$ or $x = 2.755$
Can you please calculate if your answer matches up with any of the two versions? I don't know if it's just me or the textbook got it wrong.