How to factor quadratics $(x^2 + 4x + (-357) = 0)$ I need to find $2$ factors of $-357$, which add up to $4$. Obviously one number is positive and the other is negative. I understand this and I know the factors can be $21$ and $-17$; but, how do I factor larger numbers like $-357$ without using a guess/check method? 
 A: You could just solve it using the quadratic formula.  Then, if $x_1$ and $x_2$ are the two solutions, you can factor this as $x^2+4x-357=(x-x_1)(x-x_2)$.

If you really want to factorize $357$, though, you could just test the small primes to see if they are factors.  For instance, $2$ is clearly NOT a factor, but $3$ is (because if you add up all of the digits you get a number which $3$ divides).  So you factor out a $3$ to get $357=3\cdot(119)$.
Then checking $119$, $2$, $3$, and $5$ aren't factors -- but $7$ is.  So then you have $357=3\cdot7\cdot17$.  And $17$ is prime.  So that's how you factor $357$.
Rules for Testing Small Primes: Given an integer we want to factor, here are some rules for checking whether the number is divisible by the small primes:


*

*The number will be divisible by $2$ if the last digit of the number is even.

*The number will be divisible by $3$ if the sum of the digits is divisible by $3$.  If you can't immediately tell if the sum of the digits is divisible by $3$, add the digits again (and repeat as many times as necessary).

*The number will be divisible by $5$ if its last digit is a $0$ or a $5$.

*The number will be divisible by $7$ if after you double the last digits and subtract that number from the truncated number, you end up with a number divisible by $7$.  For example: we test $1617$ by subtracting $2\cdot 7$ from $161$ to get $147$.  If you can't immediately tell that this is divisible by $7$, then let's do it again: $14-2\cdot 7 =0$.  $0$ is divisible by $7$ (I know it's weird, but $0$ is actually divisible by ALL nonzero integers), so $1617$ IS divisible by $7$.

A: By completing the square 
$$x^2 + 4x - 357 = 0 \implies (x + 2)^2 - 4 - 357 = 0 \implies (x+2)^2 = 361 \implies x= -2 \pm 19$$
A: The formula to get solutions for $ax^2+bx+c$ is $x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$, otherwise you must trial and error only with each of its factors (of 357).
