# Mixture Algebra word problem

Brand X sells 21 oz. bags of mixed nuts that contain 29% peanuts. To make their product they combine Brand A mixed nuts which contain 35% peanuts and Brand B mixed nuts which contain 25% peanuts. How much of each do they need to use?

A detailed explaination of how to get the answer would be greatly appreciated thanks!

• Welcome to MathSE! We prefer if you add some more details to your question: what have you tried and where do you get stuck? This will help other users give good answers. – Johanna Mar 21 '15 at 15:11
• Hello. Well I have no idea where to begin in this problem, I know there is an equation here somewhere but I can't identify it correctly. So far I tried [21(.29)= (.35)A + (.25)B] but that doesn't help at all because there's still 2 variables. I just simply want to know how to properly arrive at the answer, thanks. – Ambrose Mar 21 '15 at 15:18

$$(0.29)21= (0.35)A + (0.25)B.$$
The interpretation of this is that $A$ is the amount of mixed nuts of Brand A that are used, and $B$ is the amount of mixed nuts of Brand B. The left side indicates that the mixture contains $21$ ounces of nuts.
The manufacturer takes $A$ ounces of one brand of nuts and $B$ ounces of another brand of nuts to make $21$ ounces of mixed nuts.
Using just the information in the previous paragraph, you can write another equation involving $A$ and $B$. The numbers $0.29$, $0.35$, and $0.25$ were not mentioned in that paragraph, so they do not occur in the equation.