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The following series problem was in our last term test paper.

Prove that the following series is convergent\divergent.

$$\sum\limits_{n=1}^\infty \left(\frac{2014}{n}\right)^{\frac{n}{2014}}$$

Please give me a help. Thanks.

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  • $\begingroup$ What have you tried already? $\endgroup$
    – Klangen
    Nov 28, 2018 at 10:00

3 Answers 3

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Notice that $\sqrt[n]{\left(\frac{2014}{n}\right)^{\frac{n}{2014}}}=\left(\frac{2014}{n}\right)^{\frac{1}{2014}}$ and $\lim \limits_{n\to \infty}\left(\frac{2014}{n}\right)^{\frac{1}{2014}}=0$.

Therefore $\lim \limits_{n\to \infty}\sqrt[n]{\left(\frac{2014}{n}\right)^{\frac{n}{2014}}}=0<1$. What does the root test say ?

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For any $1>\epsilon>0$ and all $n$ sufficiently large ($n>2014$ at least), $(2014/n)^{1/2014}\leq \epsilon<1$. Apply the geometric series test and comparison test.

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For $n>2014$, just compare with the series $$ \sum \bigg(\frac{2014}n\bigg)^{2015/2014}, $$ which converges by the integral test.

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