# why aren't prisms archimedian solids?

I don't understand which part of the definition of an archimedian solid excludes prisms from being one. each vertex of a prism has the same polygons around it (4,4,n for a n-gonal prism), and also each vertex is symmetrical to every other vertex, and that isn't even always part of an archimedian solid's definition (see pseudo-rhombicuboctahedron). why are they not classed as archimedian solids?

• by symmetrical I meant vertex transistive – stanley dodds Mar 19 '15 at 7:09

• If the end-faces of the prisms are regular $n$ sided polygons and the side faces are squares, then every vertex has an $n$-gon and two squares, and the vertices are essentially identical, in much the same way as a truncated icosahedron is an Archimedean solid. With anti-prisms where the side faces are equilateral triangles, every vertex has an $n$-gon and three triangles, rather like a snub dodecahedron. – Henry Mar 19 '15 at 10:08