# Focus And Vertex Of An Inclined Parabola

How to find focus,vertex,directrix of a parabola like $x^2+y^2+2xy-6x-2y+3=0$. Well i know how to find those for any parabola of form $y^2=4ax$ but im just not being able to figure out a way to convert the given equation to this form. Help Please.

• Rotate the parabola, compute the focus, vertex, and directrix of the new figure, then apply the inverse rotation to them. – Lucian Mar 18 '15 at 20:21
• just a few more links explaining rotation of axes here and here and here – Mirko Mar 18 '15 at 21:00
• Hey thank you both!i just now figured it out!!Thanks a ton!!The focus is (1,1),directrix as y=x+1 and vertex (3/4,5/4). – user220382 Mar 18 '15 at 21:13