geometrical meaning of partial derivatives If $f$ is a function of $x,y,z$, then what is the geometrical mean of
$\frac {\partial f}{\partial x}$ ?
Similary what is geometrical meaning of other partial derivatives of function $f$.
Please tell ...
Thanks
 A: Well if it is difficult to comprehend the meaning of partial derivatives in the hyperspace $\mathbb{R}^4 $ then we can first talk about the simpler and easily comprehensible one $\mathbb{R}^3$- space. When we try to find the derivative of $z=f(x, y)$ at $(x_0, y_0)$ with respect to,  say $x$, then we consider $y$ to be a constant i. e. we actually consider the intersection of the surface $f(x, y)$ and the plane $y = y_0$ which gives us a curve in $y = y_0$ plane (an $\mathbb{R}^2$-space). Then as it is obvious that $\frac{\partial z} {\partial x} $ gives us the slope of tangent at the point $(x_0,y_0)$ with respect to $x$-axis.
We may now go ahead to generalize this concept for hyperspace by saying that the intersection of the hyperplane $z=z_0$ and the hypersurface $w = f(x, y, z)$ is a surface in $\mathbb{R}^3 $ and the same story repeats which has been told earlier but in the end the fact remains the same that $\frac{\partial z} {\partial x} $ denotes slope. 
A: You can think of $\frac {\partial f}{\partial x}$ as the slope in the x-direction.
A: From a geometrical point of view:
If $f$ is smooth enough, then
$d f= \frac{\partial f}{\partial x}d x+ \frac{\partial f}{\partial y}d y+ \frac{\partial f}{\partial z}d z$
is the local representation of the total differential of $f$.
It's an covector and lives in the dual of $R^3$.
The $\frac{\partial f}{\partial x}$,
 $\frac{\partial f}{\partial y}$ and $\frac{\partial f}{\partial z}$ are just
local coordinates of this covector.
