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What is the lowest possible degree of a polynomial $p(x)$ with integer coefficients which has one root

$$x = \sum_{n=1}^k\sqrt{a_n}$$ where $1 \lt a_1 \lt \cdots \lt a_k$ are non-square integers?

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    $\begingroup$ The answer will depend on common factors for the $a_i$. For example, if $a_1=2$ and $a_2=8$, you have a linear factor with the root you want. But that will not work for general $a_1$, $a_2$. $\endgroup$ – Paul Mar 3 '15 at 21:46
  • $\begingroup$ Ok so we need information of how many of them are relative prime to each other? $\endgroup$ – mathreadler Mar 3 '15 at 21:49
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The minimal degree can be $2^k$, e.g., for $a_n$ being distinct prime numbers. We see that $\sqrt{p_1}+\sqrt{p_2}+\cdots +\sqrt{p_k}$ has degree $2^k$ over $\mathbb{Q}$, and we have $$ [\mathbb{Q}(\sqrt{p_1},\ldots ,\sqrt{p_k}):\mathbb{Q}]=[\mathbb{Q}(\sqrt{p_1}+\sqrt{p_2}+\cdots +\sqrt{p_k}):\mathbb{Q}]=2^k. $$ This is explained here for a case with $k=2$.

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