When two planes have the same perpendicular vector $\overrightarrow{v}$, then they are parallel, right??
We have that the two planes $Ax+By+Cz+D_1=0$ and $Ax+By+Cz+D_2=0$ are parallel, since they have the same perpendicular vector $\overrightarrow{v}=(A, B, C)$.
The line that contains $\overrightarrow{v}$ intersects the two planes at the points $K, M$.
Then $\overrightarrow{OK}=\lambda \overrightarrow{v}=(\lambda A, \lambda B, \lambda C), \overrightarrow{OM}=\mu \overrightarrow{v}=(\mu A, \mu B, \mu C)$.
Then $\lambda A^2 +\lambda B^2 +\lambda C^2=-D_1 \Rightarrow \lambda=-\frac{D_1}{A^2+B^2+C^2}$
$\mu A^2 +\mu B^2 +\mu C^2=-D_1 \Rightarrow \mu=-\frac{D_2}{A^2+B^2+C^2}$
So, the distance between the two planes is equal to $$||\overrightarrow{KM}||=||(\mu -\lambda ) \overrightarrow{v}||=|\lambda -\mu | ||\overrightarrow{v}||=\frac{|D_1-D_2|}{\sqrt{A^2+B^2+C^2}}$$
$$$$
My questions are the following:
- At the sentence " The line that contains $\overrightarrow{v}$ intersects the two planes at the points $K, M$. " what does it mean the line that contains the vector??
- Why do we calculate the vectors $\overrightarrow{OK}$ and $\overrightarrow{OM}$ ??