Two fair dice are rolled. What is the conditional probability that at least one lands on 6 given that the dice land on different numbers?
I already know the answer, but am having some trouble understanding it.
If E is the event that at least one dice lands on 6 and F is the event that the dice land on different numbers, I need to calculate P(EF)/P(F)
According to the answer P(EF) = 2*(1/6)*5/6. I don't understand how this was calculated. Is there a specific formula for calculating P(EF)? I know P(EF) = P(E)+P(F) if the two events are mutually exclusive.
P(F) = 30/36 which makes sense because there are 36 possible outcomes, of which 30 are favorable.
Mainly just confused about calculating P(EF).