Calculating the coordinate of third point in triangle I have triangle ,where I know A coordinates (Ax,Ay), B coordinates (Bx,By) and all three angles. Now the question is : How could I calculate coordinates of C ?
Here´s the pic of  I would really appreciate your help :). Thank you

 A: I'm not going to click on the link but here are some hints on how to go about it.


*

*What angle does $\overline{AB}$ make with the $x$ axis?  (Hint: it involves the slope.)

*Since you know the angles, you can determine what angles $\overline{AC}$ and $\overline{BC}$ make with the $x$ axis by adding (or subtracting) them from the angle you found above.

*You can use these angles to find the slopes of the sides, and then equations for the lines that define the sides (using point-slope form).

*Then, solve for the common solution of those two lines, which will be point $C$.

A: 1> Calculate the values of the slopes of both AC and BC.(This can be done by finding the angle AB makes with the X axis)
2> Once you get the two slopes you can express the lines AC and BC in the point slope format.
3> Solve both the line to get the meeting point.
Or if you are comfortable with translation and rotation you could shift the image such that AB is on the X axis and A is the origin. Now solve for C since tan(alpha) and tan(beta) are now slopes. Shift the value of C back. The answer is your result.
