Trouble creating venn diagram with data I have been given data to insert into a venn diagram but I am having trouble doing so. The diagram is needed to aid finding other data. The data is given explaining which workers work on which floor in a building. The diagram would obviously consists of a 3 circle diagram, one for each floor. Here is the data I am given;
A survey was created to ask 60 workers which floor in the 3-storey building they had cause to work on.
The results were collated: 


*

*29 worked on the ground floor

*10 worked on the second, first and ground floor

*33 worked on the first floor

*12 worked ONLY on ground and first floor

*6 worked ONLY on the second floor

*2 worked ONLY on the second and ground floor

*1 worked ONLY on the second and first floor


Obviously I tried taking the data and inserting in onto the diagram as follows, but when trying to work out how many workers were on each floor I am given inaccurate results meaning my diagram is wrong.

Would someone be able to create a venn diagram out of the data given?
EDIT
After taking in some of the answers I have created the following diagram, is it possible that the number of workers doesn't have to add up to 60?

 A: When it says for instance, $29$ worked on the ground floor, this means your total for all $4$ Venn-diagram regions making up Ground floor should total to $29$.  This means that the region that is ground floor only should be $29-24=5$ (since there are $24$ in the other three regions of ground floor).  I think your regions of overlap between various sets are correct.  It's just the regions that are in only one set that need adjusting.  (And not necessarily all of those).
A: We can check the data correctness by solving the problem in another way.
We can divide workers in $7$ non-intersecting sets: $W_G, W_1, W_2, W_{G1}, W_{G2}, W_{12}, W_{G12}$ where index means floors visited by set members and correspondently $w_k = |W_k|$.
Then
$$w_G + w_{G1} + w_{G2} + w_{G12} = 29$$
$$w_{G12} = 10$$
$$w_1 + w_{G1} + w_{12} + w_{12G} = 33$$
$$w_{G1} = 12$$
$$w_2 = 6$$
$$w_{G2} = 2$$
$$w_{12} = 1$$
We can simply find from here that $(w_G, w_1, w_2, w_{G1}, w_{G2}, w_{12}, w_{G12}) = (5,9,6,12,2,1,10)$, so the sum is $45$, not $60$.
