Many special functions of mathematical physics can be understood from the point of view of the representation theory of lie groups. An example of the power of this viewpoint is given in my question here. The gist of the theory is as follows:

The general set up here is that we have a group acting on a space $X$, and we look at the space of functions on $X$ (let me write it $\mathcal F(X)$). Then there is a natural representation of $G$ on $\mathcal F(X)$.

(a) If $ X = G = S^1$ (the circle group, say thought of as $\mathbb R/\mathbb Z$) acting on itself by addition, then the solution to the problem of decomposing $\mathcal F(S^1)$ is the theory of Fourier series. (Note that a function on $S^1$ is the same as a periodic function on $\mathbb R$.)

(b) If $ X = G = \mathbb R$, with $G$ acting on itself by addition, then the solution to the above question (how does $\mathcal{F}(\mathbb{R})$ decompose under the action of $\mathbb R$) is the theory of the Fourier transform.

(c) If $ X = S^2$ and $G = SO(3)$ acting on $X$ via rotations, then decomposing $\mathcal F(S^2)$ into irreducible representations gives the theory of spherical harmonics. (This is an important example in quantum mechanics; it comes up for example in the theory of the hydrogen atom, when one has a spherical symmetry because the electron orbits the nucleus, which one thinks of as the centre of the sphere.)

(d) If $ X = SL_2(\mathbb R)/SL_2(\mathbb Z)$ (this is the quotient of a Lie group by a discrete subgroup, so is naturally a manifold, in this case of dimension 3), with $G = SL_2(\mathbb R)$ acting by left multiplication, then the problem of decomposing $\mathcal F(X)$ leads to the theory of modular forms and Maass forms, and is the first example in the more general theory of automorphic forms.

The same idea can explain how Bessel, Hypergeometric functions etc... arise geometrically. Again my question has an example of this. This table:

enter image description here

lists 7 groups and the differential equation each is related to.

My question is asking for an intuitive way to think about the 7 groups listed and what they geometrically mean, and why they relate to some invariance in Laplace's equation $\nabla^2 u = 0$. I even think there are a few different interpretations, e.g. in terms of homogeneous spaces, hyperbolic spaces, etc... so I'm kind of lost.

To give an example of what I'm hoping for, take the Euclidean Group $E_2$, it can be represented by matrices of the form

$$ g(x,y,\theta) = \left( \begin{array}{ccc} \cos(\theta) & - \sin(\theta) & x \\ \sin(\theta) & \cos(\theta) & y \\ 0 & 0 & 1 \end{array} \right)$$

Intuitively this is the group of plane motions, the group of all translations and rotations in the plane. If Laplace's equation models a problem with cylindrical symmetry, i.e. Laplace's equation is invariant under the group of plane motions, classically we end up having to solve Bessel's equation, but group-theoretically we can solve the problem with representation theory this magical way instead. That shows how Bessel's equation is just another way to say: "find a function in the plane such that when we shift it right, then shift it back left again, all locally (i.e. differentially) in polar coordinates, we get the same function". The same model holds for all equations in that table, but I don't know the geometry or pictures allowing me to see it.

Some present confusion of mine:

When I look at $SL(2,R)$ and it's matrix representation I have no intuitive picture of the group it's representing or any geometric picture (like a cylinder) to think of that tells me when solving $\nabla^2 u = 0$ will result in the Hypergeometric equation, for example.

If I try to think of $SO(3)$ as the group of rotations of a sphere I get Gegenbauer functions, but Gegenbauer polynomials give Legendre polynomials as a special case. However they also arise from the $SU(2)$ spinor representation of $SO(3)$. My guess is that this all links together because rotations can be decomposed into products of reflections, and spinor representations arise from this simple idea. But is it okay to think of $SO(3)$ as a group of 3-D Rotations and $SU(2)$ as the reflections that generate those rotations?

  • 1
    $\begingroup$ $SL(2,R)$ is connected to the spinor representation of $SO(2,1)$ and $SL(2,C)$ is connected to the spinor representation of $SO(3,1)$. The latter is common in physics because of its connection with special relativity. The wiki page on spinor representations has a table at the very end with the connections. $\endgroup$ Commented Feb 25, 2015 at 8:52
  • 4
    $\begingroup$ I am working my way through ima.umn.edu/~miller/lietheoryspecialfunctions.html and it seems to address your questions. Just a guess/suggestion. $\endgroup$
    – rrogers
    Commented Aug 15, 2015 at 12:58
  • $\begingroup$ It would be great if you could answer this question when you've read the relevant parts of Miller, I could not find an answer while browsing through that book but I may have missed it :) $\endgroup$
    – bolbteppa
    Commented Aug 15, 2015 at 13:20
  • $\begingroup$ Hi there, let me drop one of my favourite links. This is an absolutely wonderful reference on the Heisenberg group ams.org/journals/bull/1980-03-02/S0273-0979-1980-14825-9/… $\endgroup$ Commented Mar 30, 2016 at 18:53
  • $\begingroup$ Regarding the hypergeometric function, I would say that ithe fact that $\mathbb{P}^1_{\mathbb{C}}-\{0,1,\infty \}$ is a quotient of the Klein disk / Poincaré semiplane by a subgroup (of index $2$) of the group $SL_2(\mathbb{Z})$ that bears many geometric consequences on hypergeometric functions. It would be great to hear the opinion of an expert. $\endgroup$ Commented Mar 30, 2016 at 20:48

1 Answer 1


Edit: I have skimmed through http://www-users.math.umn.edu/~mille003/Lie_theory_special_functions_paper.pdf, by Willard Miller, referred to by @rrogers in the comments. In that paper, the author mentions that a class of special functions occur as matrix elements of irreducible representations: see the Peter-Weyl theorem (https://en.wikipedia.org/wiki/Peter–Weyl_theorem) and the Schur orthogonality relations (https://en.wikipedia.org/wiki/Schur_orthogonality_relations). As an example, if $G = SO(3)$, then the spherical harmonics are related to the matrix elements, when $SO(3)$ is described using Euler angles.

The author also mentions other ways in which symmetry/group theory and special functions are related (I quote: as basis functions for Lie group representations, as solutions of Laplace-Beltrami eigenvalue problems with potential via separation of variables, as Clebsh-Gordan coefficients).

It therefore seems that special functions are related to Lie groups in many different ways.

I am not well versed in special functions, but the way I think of them, which may not apply to all cases in which the functions are called special, is as special bases elements of the space of invariants of a system of differential equations (usually coming from physics), that are associated to the group of symmetries of that system.

Old answer: Finally, I can tell you a little about the geometry of the Lie groups you have mentioned, $SL(2,\mathbb{R})$, $SU(2)$ and $SO(3)$. Let me mention Helgason's books which may be useful to you too.

First, these $3$ groups are all "real forms" of the Lie group $SL(2,\mathbb{C})$. $SL(2,\mathbb{R})$ is non-compact, corresponding to a specific "real slice" of $\mathfrak{sl}(2,\mathbb{C})$ (the Lie algebra of $SL(2,\mathbb{C})$), while $SU(2)$ and $SO(3)$ are both compact, and correspond to another "real slice" of $\mathfrak{sl}(2,\mathbb{C})$; however, and this is important to spin geometry, Dirac equation and all that, $SU(2)$ is simply connected, while $SO(3)$ has fundamental group $\mathbb{Z}/(2)$. Topologically, $SU(2)$ is the 3-dimensional sphere $S^3$, while $SO(3)$ is the real projective $3$-space $\mathbb{R}P^3$, which can be thought of as $S^3$ with antipodal points identified.

Now we come to the geometric interpretation of these groups, so to speak. $PSL(2,\mathbb{R})=SL(2,\mathbb{R})/\{\pm Id\}$ is actually the group of oriented isometries of the hyperbolic plane. If you are familiar with the theory of compact Riemann surfaces, those of genus $g \geq 2$ are called hyperbolic. They can be described nicely as quotients of the hyperbolic plane by a discrete group action. I also think that hypergeometric functions can be interpreted as holomorphic (or meromorphic?) functions on a compact hyperbolic Riemann surface (Check with an algebraic geometer, or online, to get details on the genus $g$ etc.). Thus the link between $SL(2,\mathbb{R})$ and hypergeometric functions is via the hyperbolic plane. The details are unfortunately scattered in the literature, though well known to experts.

Regarding $SU(2)$, it acts naturally on the space of Weyl spinors $S = \mathbb{C}^2$ (by just matrix multiplication). But then $S \odot S$, the symmetric square of $S$, is a complex $3$-dimensional space, on which $SU(2)$ acts via the induced representation. You can check that there is actually a real slice $V \subset S \odot S$ on which $SU(2)$ acts, which actually factors through $SU(2)/\{\pm Id\}$, and which preserves a real inner product (the inner product is induced by a symplectic form on $S$), as well as a choice of orientation of $V$. Thus one gets a group homomorphism from $SU(2)/\{\pm Id \}$ into $SO(3)$, and one can check that it is actually an isomorphism.

Morale: $SU(2)$ is a double cover of $SO(3)$. The former acts on spinors, while the latter acts on vectors. Thus $SU(2)$ is the spin group $Spin(3)$ in dimension $3$.

I hope this helps!

Old Edit: As a comment, it is clear that any (linear) representation of $SO(3)$ is also a representation of $SU(2)$, but the converse is not true. There are representations of $SU(2)$, such as $S$, which are not representations of $SO(3)$. For instance, when $n$ is odd, the $n$-th symmetric square of $S$ is an irreducible representation of $SU(2)$, which is not a representation of $SO(3)$. These representations correspond to spins that are half an odd integer ($1/2$, $3/2$, $5/2$ etc), and are thus associated to fermions, rather than bosons.


You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .