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Helping my daughter with a science fair project.

We are a family with four kids, three girls and then a boy.

What is the probability of a family having four kids and the first three are girls and then a boy? So... want probability of four kids in that gender order - girl, girl, girl and then boy.

Thank you!

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    $\begingroup$ Well I'd assume just (1/2)^4 = 1/16 $\endgroup$ Feb 21 '15 at 3:47
  • $\begingroup$ i thought we'd proved prob(girl)=0.51? $\endgroup$
    – JMP
    Feb 21 '15 at 3:59
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    $\begingroup$ The answer is probably society-dependent. Whether people choose to have another child after say the second or third could depend on the sex distribution of the first couple of children. $\endgroup$ Feb 21 '15 at 3:59
  • $\begingroup$ Oh, I never thought of it that way André. $\endgroup$
    – Yorch
    Feb 21 '15 at 4:03
  • $\begingroup$ André raises another question, how many kids would one expect to need to have to get one of each gender? $\endgroup$ Feb 21 '15 at 4:53
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The probabability of any combination in which the order is given is $\frac{1}{16}$.

We must have the events $G,G,G,B$ in that order where the probability of each one is $\frac{1}{2}$. Thus the probability is:

$\frac{1}{2}\times\frac{1}{2}\times \frac{1}{2}\times\frac{1}{2}=\frac{1}{16}$

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  • $\begingroup$ Thank you! So the probability is the same regardless if we are testing for one boy at any point vs. the boy being last? $\endgroup$ Feb 21 '15 at 5:59

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