This question is an exact duplicate of:

If 2 parallel objects are traveling at 1200 m/s and 30m apart what is the minimum speed a 3rd object would have to move to intercept both objects (assuming it can only travel at 180 degrees in straight lines, horizontal to the 2 objects course). I'm not sure what to do if it is involving vectors but I managed to get this, even though its wrong... 30 x 1200= 36,000m/s


marked as duplicate by k170, Daniel W. Farlow, user147263, Arthur, N. F. Taussig Feb 20 '15 at 2:13

This question was marked as an exact duplicate of an existing question.


I'm not sure what the exact setup of this problem is but it seems like you can get the speed of the object as close to $1200 \text{ m/s}$ as you want, given enough time to intercept them.

Have the intercepting object pace the other two objects (so it's traveling alongside them). Now add a small component of velocity toward the two objects. The third object will cross paths with both of them eventually.

  • $\begingroup$ Humm imagine 2 vertical lines named A + B. A and B are traveling 1200m/s and are both 1m x 1m in size. The 3rd object is 1cm x 2cm. What is the min speed needed for that object to intercept both objects assuming it only travels in a completely horizontal lines, like a cut clean through. $\endgroup$ – user217699 Feb 19 '15 at 19:46

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