Bender's height Bender is 2m tall. He uses a machine that creates 2 clones of him self at 60% his height. Then his clones use this machine as well and create 2 more clones each at 60% of their height. If this continues what is the height of each new generation of Benders. If you can i would prefer the equation in y=mX+b format.
 A: This is not a linear problem, so a linear equation is impossible. Call Bender himself Generation $0$. If $h(n)$ is the height of a copy in Generation $n$, then $$h(n)=2(0.6)^n=2\left(\frac35\right)^n\;,$$ because the height is simply multiplied by $0.6$, or $\frac35$, each generation. Thus, $h(n)$ keeps shrinking, but at a slower and slower rate, getting closer and closer to $0$ but never quite reaching it. Here are the first few generations and the $20$-th:
$$\begin{array}{r|c}
\text{Generation:}&0&1&2&3&4&5&20\\
\text{Height:}&2&1.2&0.72&0.432&0.2592&0.15552&\approx0.000073
\end{array}$$
The number of copies in Generation $n$ is $2^n$, since each generation has twice as many copies as the previous one, so the total height of all members of Generation $n$ is $$2^n\Big(2(0.6)^n\Big)=2(2\cdot0.6)^n=2(1.2)^n=2\left(\frac65\right)^n\;.$$ This number grows, faster and faster. Here are the first few generations and the $20$-th:
$$\begin{array}{r|c}
\text{Generation:}&0&1&2&3&4&5&20\\
\text{Total Height:}&2&2.4&2.88&3.456&4.1472&4.97664&\approx76.6752
\end{array}$$
The total height of all copies in Generations $0$ through $n$ is given by the expression $$10\Big((1.2)^{n+1}-1\Big)\;.$$
A: If I understood you correctly then :
$f(0)=h=2 m$
$f(1)=0.6 \cdot h$
$f(2)=0.6 \cdot 0.6 \cdot h$
$\vdots$
$f(n)=(0.6)^n \cdot h=2 \cdot (0.6)^n $
where $f(n)$ is height of nth generation . 
