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I was wondering, what is the order of operations when it comes to multi level exponents. Couldn't find anything in google. Something like:

$$n^{n-1^{n-2^{\cdots^1}}}$$

In this case, if n equals 4, would it be correct to assume that 4^(3^(2^1)) is the correct order? And thus the answer is 262144?

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Yes to both questions.

You should include parentheses around the differences, such as $$n^{(n-1)^{(n-2)^{\cdots^1}}}$$

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No.

4^3^2 = 4^6 ; It does not equal 4^9. Multiple exponents evaluated from left to right. (4^3)^2. The power is 2*3=6. Because. First you get 4*4*4, and square that. It's alway true that you can multiply the exponents if there arent parenthesis grouping them in some way. 4^3^2^5 = 4^30

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    $\begingroup$ The most common convention for the "^" is a^b^c=a^(b^c) (or so I've been told: personally I never use it). I can assure you 100% that the standard convention for $a^{b^c}$ is $a^{(b^c)}$. $\endgroup$ – user228113 Apr 26 '17 at 14:24
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    $\begingroup$ Firstly thanks for contributing answers! Let's use MathJax to format the answer so that it is easy for people to read $\endgroup$ – Yujie Zha Apr 26 '17 at 14:28
  • $\begingroup$ Plain wrong. -1. $\endgroup$ – MPW Feb 24 '18 at 22:15

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